CS51 - Fall 2009 - Lecture 27

  • Book problem 15.4.1
       - university enrolls int NUM_STUDENTS students
       - students can take one or more courses
       - Grades for each course are between 0.0 and 4.0
       - Calculate the average for each student:
       public int[] getAverage(double[][] grades)   

       - Note: it's convenient to think about 2D arrays as matrices, but they're not always matrices. Sometimes, you will have rows without the same number of columns. A 2D array is an array of arrays!

  • Show TicTacToe demo
       - Using a multidimensional array, how can we keep track of the board?
          - private int NUM_ROWS = 3;
          - private int NUM_COLS = 3;
          - 3 by 3 array of integers: int[][] marks = new int[NUM_ROWS][NUM_COLS];
             - private int EMPTY_MARK = 0;
             - private int X_MARK = 1;
             - private int O_MARK = 2;
       - How do we check for a win?
          - need to check four cases:
             - rows all the same
             - columns all the same
             - top-left to bottom-right diagonal all the same
             - top-right to bottom-left diagonal all the same
          - Note: when we're checking for a win, we're checking if a particular player has won for the last move
             - we know the mark the player made (i.e. X or O)
             - we know the row and col position where the mark was made
       - Given
          LEFT // x value of the left of the board
          TOP // y value of the top of the board
          CELL_SIZE // the size of the an individual cell in the board
          that the user clicked at x, y, which we know is in the board
       - How do we figure out what cell/board space the user clicked in?
          x = x - LEFT;
          y = y - TOP;
          int col = (int)(x/CELL_SIZE);
          int row = (int)(y/CELL_SIZE);

  • magic square
       - a magic square is an n by n matrix
       - containing the numbers 1 through n^2
       - such that all the rows, columns and diagonals sum to the same number

  • take a few minutes and try to do a 3 by 3 magic square

  • show MagicSquares demo
       - How can we represent a magic square?
          - an n by n integer array
          - int[][] magicArray = new magicArray[n][n];
       - if n is odd, you can build a magic square with the following rules
          - put a 1 in the center of the bottom row
          - place the next number (i.e. 2 follows 1, etc) in
             - the cell one slot below and one slot to the right
                - if you fall off the bottom or right, wrap around
             - if that cell already has a number, put it in the slot above the original position

  • show MagicSquares code (specifically MagicSquare.fillSquare)
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